12 Pdf: Turbo Physics Grade

But his measured 135°C meant . The compressor efficiency (η_c) = (T₂_ideal – T₁)/(T₂_actual – T₁) = (78-25)/(135-25) = 53/110 ≈ 48%. The rest of the work became heat due to friction and turbulence. Chapter 4: The Density Battle Kael connected the compressor outlet to a small engine cylinder. More air pressure meant more oxygen molecules per volume—but the heat reduced density. Using the ideal gas law rearranged: ρ = P / (R_specific × T)

Using angular dynamics: τ = I × α, where τ = torque from turbine, I = rotational inertia, α = angular acceleration. turbo physics grade 12 pdf

T₂ = 298 K × (1.8/1.0)^0.286 T₂ = 298 × 1.8^0.286 1.8^0.286 ≈ 1.178 T₂ ≈ 351 K → 78°C (theoretical ideal). But his measured 135°C meant

At 1.8 atm and 135°C (408 K): ρ = (1.8 × 101325 Pa) / (287 J/kg·K × 408 K) ρ ≈ 182385 / 117096 ≈ 1.56 kg/m³ Chapter 4: The Density Battle Kael connected the

For air, γ = 1.4, so (0.4/1.4) = 0.286.

New density at 1.7 atm, 45°C (318 K): ρ = (1.7×101325)/(287×318) ≈ 172252/91266 ≈ 1.89 kg/m³

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