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Beginners put the friction force at ( \mu_s N ) immediately. Experts check if the ladder is impending at both ends.

Students try to write forces without the constraint equations. The rope lengths change in two reference frames.

( \frac{dU_{eff}}{d\theta} = 0 ) [ mgR \sin\theta - m\omega^2 R^2 \sin\theta \cos\theta = 0 ] [ mR \sin\theta ( g - \omega^2 R \cos\theta ) = 0 ]

The mass cancels out. A heavier ladder doesn't change the slip angle. Counterintuitive? Only until you realize both inertia and friction scale with ( M ). Problem 2: The "Double Atwood" Escape (Energy & Constraints) Difficulty: ⭐⭐⭐⭐