Convert Xsd To Java Pojo Online ✓

@XmlElement(required = false) protected Double salary;

@XmlAccessorType(XmlAccessType.FIELD) @XmlType(name = "", propOrder = "id", "name", "salary", "department") @XmlRootElement(name = "Employee") public class Employee convert xsd to java pojo online

<?xml version="1.0" encoding="UTF-8"?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:element name="Employee"> <xs:complexType> <xs:sequence> <xs:element name="id" type="xs:int"/> <xs:element name="name" type="xs:string"/> <xs:element name="salary" type="xs:double" minOccurs="0"/> <xs:element name="department" type="xs:string"/> </xs:sequence> <xs:attribute name="active" type="xs:boolean"/> </xs:complexType> </xs:element> </xs:schema> @XmlElement(required = false) protected Double salary

@XmlElement(required = true) protected String name; @XmlAccessorType(XmlAccessType.FIELD) @XmlType(name = ""

@XmlAttribute(name = "active") protected Boolean active;

@XmlElement(required = true) protected String department;

@XmlElement(required = true) protected int id;