% Max deflection fprintf('Max deflection = %.2e m\n', max(w(:)));
%% Stress Recovery % Compute curvatures at center element (using central diff) i_center = round(Nx/2); j_center = round(Ny/2); if mod(Nx,2)==0, i_center=i_center+1; end if mod(Ny,2)==0, j_center=j_center+1; end Composite Plate Bending Analysis With Matlab Code
[ \left(\frac{\partial^4 w}{\partial x^4}\right) {ij} \approx \frac{w {i-2,j} - 4w_{i-1,j} + 6w_{i,j} - 4w_{i+1,j} + w_{i+2,j}}{\Delta x^4} ] % Max deflection fprintf('Max deflection = %
%% Compute ABD Matrix A = zeros(3,3); B = zeros(3,3); D = zeros(3,3); for k = 1:num_plies theta_k = theta(k) * pi/180; m = cos(theta_k); n = sin(theta_k); % Transformation matrix T = [m^2, n^2, 2 m n; n^2, m^2, -2 m n; -m n, m n, m^2-n^2]; % Q_bar = T * Q * T_inv Q = [Q11, Q12, 0; Q12, Q22, 0; 0, 0, Q66]; Q_bar = T * Q * T'; % Integrate through thickness A = A + Q_bar * (z(k+1)-z(k)); B = B + Q_bar * 0.5 * (z(k+1)^2 - z(k)^2); D = D + Q_bar * (1/3) * (z(k+1)^3 - z(k)^3); end % For symmetric laminate, B should be zero (numerically small) B = zeros(3,3); % enforce symmetry j_center = round(Ny/2)
boundary_nodes = []; for i = 1:Nx for j = [1, Ny] boundary_nodes = [boundary_nodes, idx(i,j)]; end end for j = 2:Ny-1 boundary_nodes = [boundary_nodes, idx(1,j), idx(Nx,j)]; end boundary_nodes = unique(boundary_nodes);
%% Composite Plate Bending Analysis Using CLPT & Finite Differences clear; clc; close all; %% Material Properties (T300/5208) E1 = 181e9; % Pa E2 = 10.3e9; G12 = 7.17e9; nu12 = 0.28; nu21 = nu12 * E2/E1;
We assemble a sparse linear system ( [K] {w} = {f} ) and solve. Below is the complete code. It computes deflections, curvatures, and then stresses in each ply at Gauss points.